Help with probability question

AI Thread Summary
In the discussion, participants analyze the independence of two events related to probability problems involving a die and a coin. For part (a), they determine that events A (rolling an even number) and B (rolling a number less than 4) are not independent, as the probability of both occurring does not equal the product of their individual probabilities. In part (b), they conclude that events A (first toss is a Head) and B (all three tosses are the same) are also not independent, based on their calculated probabilities. The conversation emphasizes the importance of correctly applying the independence test, P(A and B) = P(A)P(B). Ultimately, both parts demonstrate that the events in question do not meet the criteria for independence.
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Homework Statement


(a) Suppose a fair six-sided die is rolled once. Let A be the event that an even face occurs and B be the event that a face less than 4 occurs. Are the events A and B independent? Show this mathematically.

(b) A fair coin is tossed three times. Let A be the event that the first toss is a Head and let B be the event all three are the same. Are the events A and B independent? Show this mathematically

The Attempt at a Solution


[/B]
a)
I know that:
P(A) = 1/2
P(B) = 1/2
but I don't know how to show that they are independent

b)
I know that P(A)=1/2 , P(B) = 1/8
but don't know how to show that they are independent

any help would be much appreciated
 
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You omitted the "Relevant Equations" section. What is your definition of independent? It should be an equation that you can either prove to be true or false in each part of the question.
 
FactChecker said:
You omitted the "Relevant Equations" section. What is your definition of independent? It should be an equation that you can either prove to be true or false in each part of the question.
p(AuB)=P(A) x P(B)

p(AuB)=1/4

1/4=1/2 x 1/2
1/4=1/4

therefore they are independent

Would this now be correct?
 
Mark53 said:
p(AuB)=P(A) x P(B)
I assume you mean that a test for independence is that P(A&B)=P(A)P(B). AuB would mean 'or'.
Mark53 said:
p(AuB)=1/4
Are you saying that the probability of rolling an even number less than 4 is 1/4?
 
haruspex said:
I assume you mean that a test for independence is that P(A&B)=P(A)P(B). AuB would mean 'or'.

Are you saying that the probability of rolling an even number less than 4 is 1/4?
Sorry should say AnB=P(A) x P(B) and that P(AnB)= 1/4
 
Mark53 said:
Sorry should say AnB=P(A) x P(B) and that P(AnB)= 1/4
You did not answer my question:
haruspex said:
Are you saying that the probability of rolling an even number less than 4 is 1/4?
 
haruspex said:
You did not answer my question:
no I am saying that it is 1/2
P(A) = 1/2
 
Mark53 said:
no I am saying that it is 1/2
P(A) = 1/2
No, event A is rolling an even number. A&B is rolling an even number less than four. What is the probability of that?
 
haruspex said:
No, event A is rolling an even number. A&B is rolling an even number less than four. What is the probability of that?
1/6
 
  • #10
Mark53 said:
1/6
Right. So is P(A&B)=P(A)P(B)?
 
  • #11
haruspex said:
Right. So is P(A&B)=P(A)P(B)?
this means that they are not equal which means they are not independent

does this mean for part b) that P(A&B)=1/8
 
  • #12
Mark53 said:
this means that they are not equal which means they are not independent

does this mean for part b) that P(A&B)=1/8
Yes, and yes.
 
  • #13
haruspex said:
Yes, and yes.
so this would mean that part b would be independent
 
  • #14
Checking the details of the part b answer, I think your original post has a wrong value for P(B).
 
  • #15
Mark53 said:
so this would mean that part b would be independent
Right.
 
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