Help with proton moving through magnetic field.

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SUMMARY

The discussion focuses on calculating the magnetic force and acceleration of a proton moving through a magnetic field. The relevant equation is F = q(V x B), where q is the charge of the proton, V is its velocity (5 x 106 m/s), and B is the magnetic field strength (6 x 10-2 T). The correct approach involves using the component of the magnetic field that is perpendicular to the velocity, necessitating the use of B sin(θ) in the calculations. This adjustment is crucial for accurately determining both the magnetic force and the proton's acceleration.

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  • Understanding of the Lorentz force equation (F = q(V x B))
  • Knowledge of vector components in physics
  • Familiarity with the concept of magnetic fields and their strength
  • Basic principles of kinematics, particularly acceleration
NEXT STEPS
  • Study the application of the Lorentz force in different scenarios
  • Learn about vector cross products and their significance in physics
  • Explore the effects of magnetic fields on charged particles
  • Investigate the relationship between force, mass, and acceleration in detail
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Students studying physics, particularly those focusing on electromagnetism and motion of charged particles in magnetic fields.

jhcollaz
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Homework Statement



I need help with a problem I was just given an equation (F =q VxB )at the end of class and expected to solve a problem but I am not sure what to do.
A proton is moving at speed 5x106m/s in the magnetic field of magnitude 6x10-2 T indicated in the diagram. a) find the magnitude and direction of the initial magnetic force on the proton. b)what is the magnitude of the acceleration of the proton?
The diagram and work are in the work below. I was not sure what to do so i looked through the book and found another equation.

Homework Equations





The Attempt at a Solution


http://imgur.com/l9NBN

 
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B is the strength of the magnetic field, which you are given. Not sure why you did the working that you did, it doesn't make any sense lol.
 
Your equation enables you to calculate the force = Bqv BUT this equation is used when B and v are at right angles. For your diagram you need the component of B at right angles to v.
So your equation should have BSinθ instead of B.
I hope that you can follow this!
 

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