Help with proving a transfer function?

AI Thread Summary
The discussion focuses on deriving a transfer function involving impedances Z1, Z2, and Z3. The user initially struggles with the expression for Zout and attempts to relate it to Zg. Another participant clarifies that Zout can be calculated using the formula Z2 || Z3, leading to the equivalent impedance across Vo. They explain that the total impedance seen by the source, Vg, is the sum of Zo and Z1, which is derived from voltage division principles. The conversation emphasizes the importance of correctly applying these principles to arrive at the correct transfer function.
Chandasouk
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I cannot get the Z2Z3 to appear in the bottom.

I'm saying Zout = Z2 || Z3 so that gives Z2Z3/Z2+Z3 and Zg = Z1

Then H(s) = Zout/Zg = Z2Z3/Z1Z2+Z1Z3

What am I doing wrong?
 
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You can attack this problem using voltage division. You can get the equivalent impedence across Vo and then divide it by the total impedence seen by the source, Vg.

So:

The voltage seen by Vo:
Zo = (Z3)(Z2)/(Z3+Z2)

The voltage seen by Vg:
Zi = Zo + Z1

So when you divide Zo/Zi and simplify you get the correct answer. Hope that helps! Let me know if you need further explanation.
 
Can you explain why Zi = Zo + Z1? I always thought voltage division was

Vn = Vtotal(Rn/Rtotal)

Where V is voltage and R is resistance. In our case, we would just replace the R's with Z's for impedances but I'm still not sure how you got Zi = Zo + Z1 from that
 
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