Vector Element Problem: Solving for Components of C in A - B + 3C = 0

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To solve for the components of vector C in the equation A - B + 3C = 0, first, calculate the x and y components of vectors A and B. Vector A has components of -8.40 cm (x) and 16.0 cm (y), while vector B has components of 12.6 cm (x) and -6.00 cm (y). This leads to two scalar equations: A_x - B_x + 3C_x = 0 and A_y - B_y + 3C_y = 0. By substituting the values of A and B into these equations, the components of C can be determined. The problem is simplified by recognizing that the vector equation can be broken down into these scalar components.
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Vector A has x and y components of -8.40 cm and 16.0 cm, respectively; vector B has x and y components of 12.6 cm and -6.00 cm, respectively. If A - B + 3C = 0, what are the components of C?

Not sure how to do this problem, I was thinking of adding the horizontal and vertical elements for A and B, but that wouldn't help in finding the components of C.
 
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You have a vector equation that will give two scalar equations.

\vec{A} -\vec{B} + 3\vec{C} = 0

A_{x} - B_{x} + 3C_{x} = 0
A_{y} - B_{y} + 3C_{y} = 0
 
thanks a lot, it was a whole lot simpler than I thought, I always seem to make physics problems more complicated than they should be lol
 
ramin86 said:
thanks a lot, it was a whole lot simpler than I thought, I always seem to make physics problems more complicated than they should be lol

No problem, :smile:
 
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