Help would be greatly appreciated

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A hunter aiming at a target 150 m away must account for the bullet's downward deflection due to gravity. The bullet, traveling at 290 m/s, will miss the target by approximately 1.31 m if aimed directly. To determine the correct angle to hit the target, one must set up equations based on horizontal and vertical displacements. The horizontal displacement remains constant at 150 m, while the vertical displacement is zero for a successful shot. Solving these equations allows for the calculation of the necessary angle to aim the gun accurately.
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1. A hunter aims directly at a target (on the same level) 150 m away.



2. (a) If the bullet leaves the gun at a speed of 290 m/s, by how much will it miss the target?

(b) At what angle should the gun be aimed so as to hit the target?





please help i am completely lost on this
 
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oxblackout12 said:
1. A hunter aims directly at a target (on the same level) 150 m away.

2. (a) If the bullet leaves the gun at a speed of 290 m/s, by how much will it miss the target?

(b) At what angle should the gun be aimed so as to hit the target?

please help i am completely lost on this


You should take into account that the bullet is deflected downward by the force of gravity. Calculate the time it takes the bullet to reach the target and the vertical distance traveled by the bullet during this time in free fall.

Eugene.
 
(assuming no air resistance)

t = (d / v) for horizontal displacement. The bullet is not accelerating through the horizontal motion, only the vertical motion, so don't worry about a change in speed.

With time, you can find how much gravity would cause it to drop.
 
Hi, sorry to gravedig, but I have a question on the second part of this problem. I figured out that the displacement is 1.31 m, but how do I go about finding the angle of the gun? I know you use sins, etc., but I can't figure out how you do that to incorperate 1.31 m without changing the velocity, and thus changing the dynamics of the question.
 
Hi Anony-mouse,

Anony-mouse said:
Hi, sorry to gravedig, but I have a question on the second part of this problem. I figured out that the displacement is 1.31 m, but how do I go about finding the angle of the gun? I know you use sins, etc., but I can't figure out how you do that to incorperate 1.31 m without changing the velocity, and thus changing the dynamics of the question.

I don't think you incorporate the 1.31 m in the second part. You set up the problem again, and you know the horizontal displacement is 150 m and the vertical displacement is zero for the bullet's flight. You can get two equations in two unknowns (angle and time) and solve for both.
 
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