[Highschool Physics] Kirchoff's Rules

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SUMMARY

This discussion focuses on applying Kirchhoff's Rules to analyze a circuit diagram provided via an external link. The key equations referenced are the sum of potential differences in a closed circuit (∑ ΔV = 0) and the sum of currents at a junction (∑ I (in) = ∑ I (out)). The user attempts to solve for current values I1, I2, and I3, concluding that both equations (1) and (5) may be correct, although they express uncertainty about their solution. The discussion highlights the importance of visualizing circuit diagrams for accurate analysis.

PREREQUISITES
  • Understanding of Kirchhoff's Current Law (KCL)
  • Familiarity with Kirchhoff's Voltage Law (KVL)
  • Basic knowledge of electrical circuit components (resistors, voltage sources)
  • Ability to interpret circuit diagrams
NEXT STEPS
  • Review examples of applying Kirchhoff's Laws in complex circuits
  • Study the concept of superposition in circuit analysis
  • Learn about Thevenin's and Norton's Theorems for circuit simplification
  • Explore simulation tools like LTspice for circuit analysis
USEFUL FOR

Students studying high school physics, particularly those focusing on electrical circuits, as well as educators looking for practical examples of Kirchhoff's Rules in action.

4Phreal
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Homework Statement



http://imgur.com/XXPWbCN

Homework Equations



∑ ΔV (closed circuit) = 0
∑ I (in) = ∑ I (out)

The Attempt at a Solution


So I know that the sum of the currents entering any junction in a circuit must equal the sum of the currents leaving that junction, and that the sum of the potential differences across all elements around any closed circuit loop must be zero. BUT this picture is so weird that I can't wrap my head around it. I think that I1 + I2 + I3 = 0, if one of those was negative which it can be. This means that (2) and (3) cannot be true. Then, solving for the potential difference equations, I got epsilon=-RI1+RI2 = -RI3+RI2, so I1R-I3R=0. So my answer would be both (1) and (5), but I'm not sure if that is correct. Could anyone help?
 
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4Phreal said:
So I know that the sum of the currents entering any junction in a circuit must equal the sum of the currents leaving that junction, and that the sum of the potential differences across all elements around any closed circuit loop must be zero. BUT this picture is so weird that I can't wrap my head around it. I think that I1 + I2 + I3 = 0, if one of those was negative which it can be. This means that (2) and (3) cannot be true. Then, solving for the potential difference equations, I got epsilon=-RI1+RI2 = -RI3+RI2, so I1R-I3R=0. So my answer would be both (1) and (5), but I'm not sure if that is correct. Could anyone help?

Correct .
 
4Phreal said:

Homework Statement



http://imgur.com/XXPWbCN

Homework Equations



∑ ΔV (closed circuit) = 0
∑ I (in) = ∑ I (out)

The Attempt at a Solution


So I know that the sum of the currents entering any junction in a circuit must equal the sum of the currents leaving that junction, and that the sum of the potential differences across all elements around any closed circuit loop must be zero. BUT this picture is so weird that I can't wrap my head around it. I think that I1 + I2 + I3 = 0, if one of those was negative which it can be. This means that (2) and (3) cannot be true. Then, solving for the potential difference equations, I got epsilon=-RI1+RI2 = -RI3+RI2, so I1R-I3R=0. So my answer would be both (1) and (5), but I'm not sure if that is correct. Could anyone help?
Due to my OCD, I like the images to be visible -- or at least documented.

attachment.php?attachmentid=70601&stc=1&d=1402727871.jpg
 

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