Highschool Question on Thermal Equilibrium

AI Thread Summary
The discussion revolves around setting up an equation for thermal equilibrium to determine the latent heat of fusion for ice. The user presents an experiment involving mixing ice and water, providing specific masses and temperatures. They attempt to formulate the energy transfer equation but recognize errors in their approach, particularly regarding the changing mass of water as ice melts. Clarification is sought on whether the mass change affects the equilibrium equation. The conversation emphasizes the need for a correct representation of energy transfers to solve for the latent heat of fusion accurately.
chris1
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Hi guys,
I'm having a bit of trouble with following thermal equilibrium question...

Homework Statement



Create an equation representing energy transfers of thermal energy equilibrium, that will enable one to determine the latent heat of fusion for ice.

One conducts an experiment mixing ice and water in a jug, recording the changes in mass and temperature:

The mass of the ice used ( m_{i} ) = 0.10kg

The initial temperature of the ice ( T_{i} ) = -15°C

The initial mass of the water ( m_{w} ) = 0.45kg

The initial temperature of the water ( T_{w} ) = 23°C

Final Temperature of mixture ( T_{f} ) = 16°C

Specific heat capacity of water ( c_{w} ) = 4.2 kJ kg^{-1}°C^{-1}

Specific heat capacity of ice ( c_{i} ) = 2.1 kJ kg^{-1}°C^{-1}So one must set up an equation of thermal equilibrium, that will allow for the value for the latent heat of fusion of ice (l) can be determined.

Homework Equations


c = \frac{Q}{mΔT}

For changes of state:
Q = ml

The Attempt at a Solution



Here is my attempt of working it out:

(m_{i} * c_{i} * 15°C) + (m_{i} * l) + (m_{i+w} * c_{w} * 16°C) = (m_{i+w} * c_{w} * 7°C)

I know my solution isn't correct due to cancelling of terms but I don't know what to do to fix it. The answer isn't in the textbook either.

Thanks for the feedback guys :smile:
 
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heat absorbed by ice and the water due to fusion of ice will be

(mi * ci * 15°C) + (mi * l) + (mi * cw * 16°C)

and heat given up by initially hot water will be

(mw * cw * 7°C)
 
mukundpa said:
heat absorbed by ice and the water due to fusion of ice will be

(mi * ci * 15°C) + (mi * l) + (mi * cw * 16°C)

and heat given up by initially hot water will be

(mw * cw * 7°C)

So would that mean:

(mi * ci * 15°C) + (mi * l) + (mi * cw * 16°C) = (mw * cw * 7°C)

But wouldn't the mass on the right side of the equation be constantly changing as the ice melts, or is that irrelevant ?
 
chris1 said:
So would that mean:

(mi * ci * 15°C) + (mi * l) + (mi * cw * 16°C) = (mw * cw * 7°C)

But wouldn't the mass on the right side of the equation be constantly changing as the ice melts, or is that irrelevant ?

Imagine that the material comprising the original mass of the ice, and the mass comprising the original mass of the water are kept separate from one another by a thin invisible membrane. Both masses are allowed to thermally equilibrate with one another. Afterwards the membrane is removed.
 
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