Hooke's law and wave velocity related problem

AI Thread Summary
The discussion revolves around a problem involving Hooke's law and wave velocity in a string. Initially, the user incorrectly assumed that increasing the extension from Y to 1.5Y would result in a wave velocity increase to 1.5V. Upon further analysis, it was clarified that the frequency remains constant, leading to a reevaluation using relevant equations. The correct relationship derived indicates that the new wave velocity V' is approximately 1.21V, considering the mass per unit length and tension of the string. The conversation highlights the importance of understanding the effects of tension and extension on wave velocity in strings.
harini07
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Homework Statement


The extension in a string, obeying hooke’s law is Y when wave velocity in it is V. if extension is increased to 1.5Y, then wave velocity V’ becomes?

1) V' =V. 2)V'= 1.22V . 3)V'=1.5V. 4) V'=0.75V.

Homework Equations


wave velocity= frequency*wave length.

The Attempt at a Solution


the frequency will be unchanged in both the cases, so v/v' = Y/1.5Y , which gives V'= 1.5V. but this is not the answer. where did i go wrong?
 
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harini07 said:
The extension in a string, obeying hooke’s law is Y when wave velocity in it is V.
Do you mean tension?
 
DrClaude said:
Do you mean tension?
nope. it's the extension and not tension.
 
So your are simply changing the length of the string.
harini07 said:
the frequency will be unchanged in both the cases
Have you ever played a guitar (or seen someone playing one)?
 
DrClaude said:
So your are simply changing the length of the string.

Have you ever played a guitar (or seen someone playing one)?
except in movies no.
 
Think about how someone changes the notes on a guitar.

By the way, it would be helpful if you came up with more "relevant equations."
 
DrClaude said:
Think about how someone changes the notes on a guitar.

By the way, it would be helpful if you came up with more "relevant equations."
in particularly? there is this hooke's law which states F(force) = -K(spring constant)*x (extension). how to relate this with wave velocity?
 
  • #10
I realize now that the problem statement is not clear. How is the extension changed? By taking a longer length of the same string, or stretching it? I was assuming the former.
 
  • #11
Do you know the equation for the wave velocity of a string as a function of the string tension? The equation has to take into account the fact that the string has mass.
 
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  • #12
Chestermiller said:
Do you know the equation for the wave velocity of a string as a function of the string tension? The equation has to take into account the fact that the string has mass.
Yup. V=√(T/mass per unit length). Substituting T for Y*area*extension/original length. Since the other components like mass, length,Young's modulus,area are unchanged, I'm equating V/V' =√(y/1.5y). Which gives V/V' = 0.82. thus I'm getting V' = 1.21V. Is this method correct?
 
  • #13
harini07 said:
Yup. V=√(T/mass per unit length). Substituting T for Y*area*extension/original length. Since the other components like mass, length,Young's modulus,area are unchanged, I'm equating V/V' =√(y/1.5y). Which gives V/V' = 0.82. thus I'm getting V' = 1.21V. Is this method correct?
Yes.
 
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