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Hooke's Law

  1. Jun 19, 2007 #1
    1. The problem statement, all variables and given/known data

    It takes 2.11 J of work to stretch a Hooke's law spring 6.08 cm from its unstressed length. How much the extra work is required to stretch it an additional 6.93 cm?


    2. Relevant equations

    F = -kx, W = Fd

    3. The attempt at a solution

    I first solved for Force by dividing 2.11J by 0.0608 m, then I just took that value and multiplied by 0.0693. I am not sure if I'm doing the correct thing. Is there a need to solve for k?

    Thank you very much!
     
  2. jcsd
  3. Jun 20, 2007 #2
    nvm I got it.
     
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