- #1
Momentum09
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Homework Statement
It takes 2.11 J of work to stretch a Hooke's law spring 6.08 cm from its unstressed length. How much the extra work is required to stretch it an additional 6.93 cm?
Homework Equations
F = -kx, W = Fd
The Attempt at a Solution
I first solved for Force by dividing 2.11J by 0.0608 m, then I just took that value and multiplied by 0.0693. I am not sure if I'm doing the correct thing. Is there a need to solve for k?
Thank you very much!