That would give the total elongation from the unweighted position, not the additional elongation.flyingpig said:Shouldn't m = 70g instead of 20g?
Hooke's Law is a principle in physics that states the force applied to a spring is directly proportional to the amount of stretch or compression of the spring.
To find the spring constant using a 50g mass and 7.0cm stretch, you can use the formula k = mg/x, where k is the spring constant, m is the mass in kilograms, and x is the stretch or compression in meters. In this case, you would convert the mass of 50g to 0.05kg and the stretch of 7.0cm to 0.07m. Then, you can plug these values into the formula to calculate the spring constant.
The spring constant is typically measured in units of newtons per meter (N/m) or kilograms per second squared (kg/s2).
The mass does not directly affect the spring constant. The spring constant is determined by the characteristics of the spring itself, such as its material and shape. However, the mass can indirectly affect the spring constant by changing the amount of stretch or compression of the spring.
Hooke's Law is applicable to most elastic materials, as long as the force applied is within the elastic limit of the material. However, there may be some materials that do not follow Hooke's Law due to their unique properties.