Horizontal spring-block system

  • Context: Undergrad 
  • Thread starter Thread starter Blogical
  • Start date Start date
  • Tags Tags
    Horizontal System
Click For Summary
SUMMARY

The discussion focuses on deriving the formula for the time period of a horizontal spring-block system with a spring of mass 'm'. It establishes that the system executes periodic motion and provides two approaches for finding the solution: an approximate method that adds m/3 to the mass of the block for the lowest frequency, and an exact method that involves setting up the equations of motion for the spring, which is treated as a wave equation with specific boundary conditions. The conversation emphasizes the importance of understanding the kinetic energy in relation to the block's velocity and the implications of the spring's mass on the system's dynamics.

PREREQUISITES
  • Understanding of harmonic motion and periodic systems
  • Familiarity with wave equations and boundary conditions
  • Knowledge of kinetic energy concepts in physics
  • Basic principles of mass distribution in mechanical systems
NEXT STEPS
  • Study the derivation of the time period for a spring-block system with mass
  • Learn about wave equations and their applications in mechanical systems
  • Explore the effects of mass distribution on oscillatory motion
  • Investigate the differences between horizontal and vertical spring-block systems
USEFUL FOR

Physics students, mechanical engineers, and anyone interested in the dynamics of oscillatory systems will benefit from this discussion.

Blogical
Messages
26
Reaction score
0
Can anybody derive and give the formula for the time period of a spring-block system placed horizontally having a spring with a definite mass 'm"?
Considering it will still execute periodic motion or else what will be the physical nature of such a system?
 
Last edited:
Physics news on Phys.org
If you want an approximate solution for the lowest frequency of the system, assume the spring stretches linearly along its length and find its kinetic energy in terms of the velocity of the block. IIRC, ths is the same as adding m/3 to the mass of the block.

If you want an exact solution, set up the equations of motion for the spring (which is equivalent to the wave equation) and solve it with the boundary conditions (fixed at one end and the block attached to the other).
 
AlephZero said:
If you want an approximate solution for the lowest frequency of the system, assume the spring stretches linearly along its length and find its kinetic energy in terms of the velocity of the block. IIRC, ths is the same as adding m/3 to the mass of the block.

If you want an exact solution, set up the equations of motion for the spring (which is equivalent to the wave equation) and solve it with the boundary conditions (fixed at one end and the block attached to the other).
Is the approximate solution equivalent to that of the vertical spring-block system where it is by adding m/3?
How can that be possible?
How to set the equation when the spring has mass, won't the physics be different??
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 24 ·
Replies
24
Views
2K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 11 ·
Replies
11
Views
5K
  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 27 ·
Replies
27
Views
5K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K