Horizontal spring with friction

AI Thread Summary
The discussion revolves around calculating the coefficient of kinetic friction for a mass released from a compressed spring. The spring has a constant of 105 N/m and is compressed by 0.1 m with a 2 kg mass. The work done by the spring is calculated using the formula for spring potential energy, and the energy lost to friction is equated to this work. The key equation derived is 0.5*k*x0^2 = C * mg * distance, where x0 is the initial compression and distance is the movement after release. The conversation emphasizes using conservation of energy to solve the problem effectively.
Ali 2
Messages
22
Reaction score
1

Homework Statement


A spring with negligible mass has a constant of 105 N/m. It has been compressed horizantally with a 2 kg mass for a distance of 0.1m. If the mass has moved after release for a distance of 0.25m, what is the coefficient of kinetic friction between mass and horizontal surface.



Homework Equations


F=-kx (spring force)
f= C N, f is friction, C is the kinetic friction coefficient, and N is the force exerted on the mass by the horizontal surface


The Attempt at a Solution


 
Physics news on Phys.org
i would recommend using work to solve this problem.
Work=force*distance
also work done by a spring is .5*k*x^2
 
Conservation of energy would be the easiest way to solve this.
What happens to the potential energy initially stored in the spring?
 
hello
ok the work done by the spring is 0.5*k*x02 - 0.5*k*x12
we know that x0=-0.1m
but what is x1, since the 0.25m given in the question is the distance not the displacement??!?
 
ok i see what you mean ap123
the energy stored initially = the work done by the friction force
0.5*k*x0^2= C * mg * distance
 
Yes, you've got it :)
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top