How Can Calculus Help Position the Center of Mass in a Hemiwasher?

Seda
Messages
70
Reaction score
0
Question Details:
I have two circles centered at the origin, one with radius A and the other with radius b.

Looking at the hemiwasher (area between) the circles form above the x axis, find the values of A and B that place the center of mass within the hemiwasher itself, not in the open middle space.

What i think i has solved so far: not necesseraly accurate:
I solved the Y value of the center of mass in terms of A and B to be::Y= (4(A^2+AB+B^2))/(3pi(A+B))

Please Help!

how can I use this to find values of a and b that put the y coordinate of the center of mass between a and b?

B is the smaller radii; the density is constant, so it is irrelvant.
 
Last edited:
Physics news on Phys.org
In other words, you want Y between A and B. You need to find A and B such that
A\le \frac{4(A^2+AB+ B^2)}{3\pi (A+B)}\le B

You won't be able to find specific values of A and B, of course. You want to find a relation between A and B that will guarantee that inequality. I would recommend that you look at
A\le \frac{4(A^2+AB+ B^2)}{3\pi (A+B)}
and
B\ge \frac{4(A^2+AB+ B^2)}{3\pi (A+B)}
seperately.

Those should give you two relations between A and B. Both need to be satisfied.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top