How can I determine the force at support B in a rigid bar system?

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To determine the force at support B in a rigid bar system, the sum of vertical forces must equal zero for static equilibrium. The force diagram should include all acting forces, and moments can be calculated about any point except B to find the necessary force. The total force acting on the system was calculated as 166N by summing the known forces of 33N, 4.4N, and 129N. The 129N figure is derived from a previous part of the problem, confirming its validity. Understanding these principles simplifies the calculation of forces in rigid body systems.
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Homework Statement



Please refer to the image.

Homework Equations



Sum of clockwise moment=sum of anticlockwise moment

The Attempt at a Solution



I had drawn out the force diagram and listed out the information required.

The question asks me to find force acting by the support B.

I troubled myself by taking moments about A and multiplying every forces with their respective distances from A.

However the answer was simple, they just added all other forces together, 33 + 4.4 + 129 = 166N.

I can't figure out where is the pivot. Or is there even a pivot? What's the theory behind this calculation?
 

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But how was the 129N figure obtained? You'd need to take moments to derive that.
 
Haruspex, the 129N is obtained from another part of the question which is correct.
 
coconut62 said:
Haruspex, the 129N is obtained from another part of the question which is correct.
Then it is indeed simple to determine the force at B in the way they use. For the system to be static, the sum of the vertical forces must be 0. You could also deduce it by taking moments about anywhere along the line except B.
 
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