How can I effectively use substitution to evaluate this integral?

htoor9
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Homework Statement



Evaluate the integral.

Int((x+5)(x-5)^(1/3)dx

Homework Equations


The Attempt at a Solution



I've attempted the problem but subsitution doesn't seem to do anything, as du = dx if u = x-5, which doesn't cancel anything.
 
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That's exactly the substitution you want to go with. If u=x-5 then x=u+5, which you can use in the other factor in the integrand.
 
Tom Mattson said:
That's exactly the substitution you want to go with. If u=x-5 then x=u+5, which you can use in the other factor in the integrand.

So then what? I have integral of (u+10)(u)^(1/3) du.
 
htoor9 said:
So then what? I have integral of (u+10)(u)^(1/3) du.

Expand the u^(1/3) into both terms. It should be easy to integrate then.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...

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