How Can I Find Eigenvalues and Normalized Eigenvectors for a Matrix?

debjit625
Messages
40
Reaction score
0

Homework Statement


Find the eigen values and normalized eigen vectors for the matrix

cosθ sinθ
-sinθ cosθ

2. The attempt at a solution
Well I did the eigen values hope they are correct but can't solve for eigen vectors

Eigen values are
λ = cosθ ± isinθ

on solving for eigen vector for eigen value λ = cosθ + isinθ ,I got
x + iy = 0 ,hence only solution x = y = 0 which is not the solution I guess (eigen vector can't be null vector)
or could I take y = i and x = 1 then it is solvable but again can I take imaginary numbers ?

Thanks
 
Physics news on Phys.org
debjit625 said:
x + iy = 0 ,hence only solution x = y = 0

x and y are not necessarily real.
 
That means I take y = i and x = 1.
Thanks.
 
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...
Back
Top