How can I integrate (Sin^4(x)*Cos^4(x)) without a calculator?

Click For Summary

Homework Help Overview

The problem involves finding the integral of (Sin^4(x)*Cos^4(x)) with respect to x without the use of a calculator. The discussion centers around techniques for integrating trigonometric functions, particularly focusing on manipulation and substitution methods.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss various methods for simplifying the integral, including the use of u-substitution and expressing the function in terms of sine and cosine. Some mention the potential of using Euler's formulas for integration.

Discussion Status

There is an ongoing exploration of different approaches to the integral, with participants sharing their attempts and questioning the effectiveness of certain methods. While some guidance has been offered regarding algebraic manipulation and the use of reduction formulas, no consensus on a definitive method has been reached.

Contextual Notes

Participants note the challenge posed by the even powers of sine and cosine and express uncertainty about the expected form of the final answer, indicating a lack of clarity on the problem's requirements.

Alabran
Messages
27
Reaction score
0

Homework Statement



Find the integral of (Sin^4(x)*Cos^4(x)) in respect to x without using a calculator.

Homework Equations



Sin^2(x) + Cos^2(x) = 1
Sin^2(x) = (1-Sin(2X))/2
Cos^2(x) = (1+Sin(2X))/2
Sin(2x) = 2Sin(x)Cos(x)
Cos(2x) = Cos^2(x) - Sin^2(x)

The Attempt at a Solution



I've been attempting to manipulate the equation so-as-to isolate a chain rule factor so I can use the U subsitution method on the problem. Unfortunately, my efforts so far have been fruitless.
 
Physics news on Phys.org
Unfortunately these are both even powers, so you won't be able to get a u-substitution out of it (at least not a trivial one). You can do some sneaky algebra to get it into an easily integrable form, or just put it all in terms of sine or cosine to a power, and use a reduction formula.
 
Sin^4(x)*Cos^4(x) = (sin(x)cos(x))^4 = ((1/2)Sin(2x))^4

than i would use Eulers formulas:

sin(b) = (e^ib-e^-ib)/(2i)

cos(b) = (e^ib+e^-ib)/(2)

Have also tried using Eulers formulas?
My favorite in integrating trigonometric functions.
 
so you can express the Sin^4(x)*Cos^4(x) as

(-1/16)*(2cos8x - 8cos4x + 6)

can have done some errors, it is very late now in sweden hehe
 
I haven't tried the Euler's forumula method, though I doubt that is what is intended.

In class, the answer to that and several other similar problems were put up in random order to show where we should be at the end. The ultimate answer was quite clean, just a sum or difference of trigonometric fractions of different powers. I don't quite remember the exact answer, though I believe the denominators were 128.

Thank you all for your help in the meantime.
 
{should be (-1/16^2)*(2cos8x - 8cos4x + 6)

yes:)

Eulers formula ALWAYS work, i have never seen a trigonometric function that it don't works on. You don't have to remember identities and so on, just Euelers two formulas hehe
 
Thank you for your help Malawi, that's a start for me, though I don't believe that's the answer my teacher is looking for. I'll try manipulating the Euler's formula some more.
 
No it is not the answer, i just said that you can express (sin^4(x)cos^4(x)) as that..

and yeah, forget the (-1/16^2) , shoulb be (1/16^2) = 1/256
 
Last edited:

Similar threads

  • · Replies 5 ·
Replies
5
Views
3K
Replies
5
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 14 ·
Replies
14
Views
1K
Replies
5
Views
2K
Replies
3
Views
2K
Replies
9
Views
2K
  • · Replies 27 ·
Replies
27
Views
4K