How can I optimize my homework solutions for efficiency and accuracy?

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Homework Statement


http://img7.imageshack.us/img7/1826/43544187.jpg


Homework Equations





The Attempt at a Solution


whats wrong with my answers? everything looks right to me... :S
 
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The only thing wrong that I see is that you haven't answered the question. You said that the volume will be minimized. You have given x, but you haven't found y and have not said what the dimensions are.
 
HallsofIvy said:
The only thing wrong that I see is that you haven't answered the question. You said that the volume will be minimized. You have given x, but you haven't found y and have not said what the dimensions are.

y=2500/17.12

the thing is, i only have to choose the right answer from those drop down menu boxes..
so i must of chosen something wrong.. but what? i don't see any mistakes
 
okay my derivatives look fine.. when f'(x)=0 x=17.1
f''(x) > 0 for x>0.. that's right because if plugging in a negative number i will get f''(x) = -..

so what's wrong?
 
can someone please help me?
 
why are u guys ignoring this post? is it something that i said?
for the last part where it says it will be relative min, when x=___
would it be -21.5446 ?
i got it by getting the second derivative equal to 0
 
One of your entry boxes says "This implies that the surface area is given in S only..."
Except for this, everything else it looks fine.

Here's a tip you might consider. Many or most of the problems you have posted have oddball numbers such as a volume of V = 2500.1055 cm^3.
I did all of my calculations using V, and replaced V only in the very last step. This saved my from writing 2500.1055 a bunch of times.

For example, A = x^2 + 4V/x. It's easy to get dA/dx = 2x -4V/x^2. Rewriting this as dA/dx = 2x -4Vx-2, it's easy to get the second derivative and verify that it's positive for all x > 0.
 
Mark44 said:
One of your entry boxes says "This implies that the surface area is given in S only..."
Except for this, everything else it looks fine.

Here's a tip you might consider. Many or most of the problems you have posted have oddball numbers such as a volume of V = 2500.1055 cm^3.
I did all of my calculations using V, and replaced V only in the very last step. This saved my from writing 2500.1055 a bunch of times.

For example, A = x^2 + 4V/x. It's easy to get dA/dx = 2x -4V/x^2. Rewriting this as dA/dx = 2x -4Vx-2, it's easy to get the second derivative and verify that it's positive for all x > 0.


i did it this way.. i substituted V only at the very end and i got the same answers..
and about the "This implies that the surface area is given in S only..." yeah i didnt read it carefully but still. now i got it tnx!
 
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