How can I prove the trig identity sinxcosxsec^2x = tanx?

AI Thread Summary
To prove the identity sinxcosxsec^2x = tanx, start by rewriting sec^2x as tan^2x + 1. This leads to the expression sinxcosx(tan^2x + 1), which simplifies to tan^2xsinxcosx + sinxcosx. By substituting secant as 1/cosine, the equation can be transformed into a more manageable form. Canceling the cosines ultimately leads to the desired result, confirming the identity. The discussion emphasizes the importance of understanding trigonometric identities and their relationships.
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1. How do I prove sinxcosxsec^2x=tanx



Homework Equations


sec^2x = tan^2x + 1


The Attempt at a Solution




sinxcosx(tan^2x + 1)
tan^2xsinxcosx +sinxcosx
sin^2x/cos^2x*sinxcosx + sinxcosx - is this valid?

I'm not sure what I've done is even correct - but it doesn't seem to be going anywhere helpful?

 
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Rewrite secant squared as 1/cos squared. The you'll have (sincos)/(coscos). Cancel cosines and you're done. I'll edit this from my computer and add arguments later!
 
secant = 1/cosine
cosecant = 1/sine
cotangent = 1/tangent
 
iRaid said:
secant = 1/cosine
cosecant = 1/sine
cotangent = 1/tangent

SOHCAHTOA. qed
 
Many thanks for your help
 
The Chaz said:
SOHCAHTOA. qed
Wasn't that Lewis and Clark's indian guide?
 
No, this is the one that's featured on the new US coins ;)
 
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