How can I simplify this integral with a variable exponent in the denominator?

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Homework Statement


\int(x^4+2x^2+x+1)/(x^2+1)^x


The Attempt at a Solution


am I supposed to multiply out the denominator then do u sub?
 
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nevermind i think its arctan
 
It isn't anything if the exponent on that denominator is really "x"! If it was supposed to be "2", I recommend dividing the fraction our so that you have a polynomial plus a "proper fraction" of the form \frac{ax+ b}{x^2+ 1}. That you divide into two parts: \frac{ax}{x^2+1} and \frac{1}{x^2+ 1}. The first uses the simple substitution u= x^2+ 1 and the second is an arctan.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...

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