How can integration by parts be used to solve this integral?

jpd5184
Messages
76
Reaction score
0

Homework Statement



integral of x^2ln(x)dx

Homework Equations





The Attempt at a Solution



u=ln(x)
du= 1/x
dv=x2dx
x^3/3

integral x^2ln(x)dx = ln(x)x^3/3-intergral(x^3/3)(1/x)
 
Physics news on Phys.org
jpd5184 said:

Homework Statement



integral of x^2ln(x)dx

Homework Equations





The Attempt at a Solution



u=ln(x)
du= 1/x
dv=x2dx
x^3/3

integral x^2ln(x)dx = ln(x)x^3/3-intergral(x^3/3)(1/x)
You're on the right path. Just continue what you're doing, but simplify the integrand on the right. Don't forget dx or the constant of integration, though.

Here's the work in LaTeX. Click the equation to see what I did.
\int x^2 ln(x)dx = \frac{x^3}{3}ln(x) - \frac{1}{3}\int \frac{x^3}{x} dx + C
 
The natural logarithm is also a function recognized by LaTeX. It has the code \ln x. Its inverse, the exponential function in the base e also has a code \exp x.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

Similar threads

Back
Top