How Can the Alternating Series Test Assume N=1?

georg gill
Messages
151
Reaction score
6
Alternating series test:

1. All the u_n are all positive

2. u_n\geq u_{n+1} for all n \geq N. For some integer N

3. u_n \rightarrow 0


I thought it would hold with 2. and that the su m of the N first terms were not \infty

Here is the theroem just in case:

http://bildr.no/view/1047382

Here they assume N=1 how can they do that?
 
Physics news on Phys.org
georg gill said:
Alternating series test:

1. All the u_n are all positive

2. u_n\geq u_{n+1} for all n \geq N. For some integer N

3. u_n \rightarrow 0


I thought it would hold with 2. and that the su m of the N first terms were not \infty

How can the sum of the first N terms ever equal infinity?? If you add up finitely many real number, then you never get infinity.

Here is the theroem just in case:

http://bildr.no/view/1047382

Here they assume N=1 how can they do that?

The proof for arbitrary N is very similar. Try to prove it yourself!
(or even better: reduce to the case N=1)
 
Back
Top