How Can You Simplify a 3x3 Matrix Determinant with Variables a and b?

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Homework Help Overview

The discussion revolves around simplifying the determinant of a 3x3 matrix that includes variables a and b. The original poster is attempting to reduce the matrix to row echelon form while ensuring that the leading diagonal elements remain linear in terms of a and b.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • The original poster describes their attempt to achieve row echelon form but encounters cubic terms in the diagonal elements. Some participants suggest computing the determinant directly and factoring the expression, while others explore specific numerical values for a to identify patterns in the factorization.

Discussion Status

The discussion is ongoing, with various approaches being explored. Some participants have offered suggestions for computing the determinant and factoring, while the original poster continues to seek a method that avoids cubic terms in the diagonal. There is no explicit consensus, but different strategies are being considered.

Contextual Notes

The original poster has expressed frustration over the complexity of the problem, indicating that it should be straightforward but has proven challenging. There is an emphasis on maintaining linearity in the diagonal elements, which may be a constraint influencing the discussion.

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Homework Statement



I've attached the problem, it involves reducing a 3x3 matrix determinant to row echelon form, but the leading diagonal elements have to be linear in a and b afterwards.

Homework Equations




The Attempt at a Solution



I've managed to convert it to row echelon form by: r3-ar2 ; r2-ar1 ; r3-br2
The problem is that this leaves a diagonal element having cubic terms. Can anyone see a way to acomplish this? Should be an easy problem, but I've spent over an hour trying different combinations.
 

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I recommend just computing the determinant and doing some simple algebra to factor the resulting expression.
 
AKG said:
I recommend just computing the determinant and doing some simple algebra to factor the resulting expression.

I also tried that, to no avail.
 
Koranzite said:
I also tried that, to no avail.

The factorization is not immediately obvious, but what finally worked for me was to look at the determinant for two different numerical values of a (namely, a = 0 and a = 1) and in each case to factor the resulting polynomial in b. Some factors are the same for both values of a, and some others differ in such a way that you can easily figure out what they are as functions of a. You end up with a factorization exactly of the required type.

RGV
 

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