How Do I Apply Binomial Expansion for x^{-1/2}(2-x)^{-1/2} Approximations?

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Homework Statement


<br /> x^{-1/2}(2-x)^{-1/2}<br />

1) approximate to lowest order in x
2) approximate to next order in x

Do I apply the binomial expanion?

Homework Equations


The Attempt at a Solution

 
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That seems like a good idea.
 
<br /> <br /> x^{-1/2}(2+x/2)<br /> <br />

<br /> <br /> 2x^{-1/2}(1/2+x^{1/2})<br /> <br />

lowest order is 2x^(-1/2)?
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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