How Do I Approach a Steady State Current Problem?

AI Thread Summary
The discussion centers on a student's confusion regarding a steady state current problem in basic electronics. The student attempts to solve the problem by assuming that in steady state, inductors behave as short circuits and capacitors as open circuits, leading to a simplified circuit with a total resistance of 48 ohms. They calculate the current using Ohm's Law, arriving at a value of 0.25A. The student expresses uncertainty about whether the question is a trick. Clarification on the concept of steady state current and its implications in circuit analysis is sought.
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Homework Statement


Hello,
I've just done a paper on basic electronics and I'm stuck on the last question. I don't know how to go about doing the question.

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Homework Equations


N/A


The Attempt at a Solution


I don't know how to even start with the question. I've tried googling "steady state current", "steady state current circuit", "how to .." and so on but nothing relevant seems to be coming up. I've also tried to ask my friends who are a year ahead and they can't remember how to do it.
 
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I assume steady state meaning DC which means inductor is a short circuit, it become 0ohm and disappeared. Cap become an open and the 30ohm on the right disappeared. So you only have a 12V battery connecting to a 30ohm and a 12ohm in series which give a total of 48ohm

So the current I=V/R = 12/48=0.25A!

Is this a trick question?
 
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