How do I calculate the height on a ramp for a rolling ball?

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To calculate the height of the ramp for a rolling ball, use trigonometric relationships involving the ramp's angle. The distance the ball travels up the ramp is known to be 0.132 meters. By applying the sine function, where height equals the distance up the ramp multiplied by the sine of the ramp's angle (35 degrees), the height can be determined. This approach simplifies the problem by relating the height to the ramp's distance as part of a right triangle. The correct application of these trigonometric principles will yield the desired height above the ground.
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I am confused as to how i solve for height in this problem. I can solve for the distance up the ramp the ball goes but not for the height above the ground.

The problem states: A steel ball has a mass of 45 grams and a diameter of 2.2 cm. The ball is moving and rolling at an initial velocity (not known) when it starts rolling up a 35 degree ramp and comes to a stop after turning 12 revolutions.

I solved for how far up the ramp the ball went by taking the 12 rev *2π rad * .011m /1 rev / 2π rad and got .132m.

I have looked at all the equations that i have but can't figure out how to solve for how high the ball goes up?
 
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right triangles

You have the angle of the ramp. Consider it as a right triangle--what trig relationships might relate height to distance up the ramp (which is the hypotenuse)?
 
thanks...i knew it was something very simple that i was missing
 
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