How do I calculate Vo/Vs for a potentiometer circuit with varying resistance?

AI Thread Summary
To calculate Vo/Vs for a potentiometer circuit with varying resistance, the resistance is divided into two parts: αR and (1-α)R. The total resistance seen by the circuit is R(1-α), and the voltage can be determined using Ohm's Law, where Vo is related to the current I and the total resistance. The user suggests that the voltage across the potentiometer can be expressed as ((ΣR)/I)Vs. The discussion highlights the importance of understanding the configuration of the potentiometer and its impact on voltage division. Proper formatting for equations is also noted as a point of improvement.
tanky322
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Homework Statement


In the circuit below, the wiper divides the potentiometer resistance between \alpha R and\ (1- alpha R), 0 \leq\alpha \geq 1. Find Vo / Vs

Schematic1.jpg

Homework Equations



KVL
KCL

The Attempt at a Solution



Im thinking that the Pot. Resistance will be R +(1-\alpha)R. Then to find the voltage (R +(1-\alpha)R)I
 

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You can ignore the resistance of the main part of the pot to ground that is below the wiper because it is in parallel with a short circuit.
The resitance of the pot is simply, R - alphaR = R(1-alpha)
 
So would the answer be:

((\SigmaR)/I)Vs


Sorry about the formatting, I need to learn how to use the system.


Thanks


Andrew
 

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