How do I convert c=9e^((-5/2)∏j) to component notation?

AI Thread Summary
To convert the expression c=9e^((-5/2)∏j) to component notation, understanding Euler's formula is essential, as it relates complex exponentials to trigonometric functions. The expression can be rewritten using Euler's formula, where e^(jθ) = cos(θ) + jsin(θ). The conversion involves identifying the real and imaginary parts of the expression. Participants in the discussion express uncertainty about the approach and seek clarification on applying complex numbers in this context. A clearer explanation of Euler's formula and its application to this problem is requested for better understanding.
Sastronaut
Messages
68
Reaction score
0

Homework Statement



Convert the following to component notation:

c=9e^((-5/2)∏j)

Homework Equations





The Attempt at a Solution


I am not very sure how to approach this problem...recently in my electronics course we discussed how we can us real and imaginary numbers and complex math...any help would be greatly appreciated; just a point in the right direction to get me started on the problem. thanks pf!
 
Physics news on Phys.org
Euler's formula - ring a bell?
 
that's a negative ghost rider...could you explain further voko? :)
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Back
Top