How do I find the derivative of f(x)=x+9/x without using the power rule?

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Homework Statement


This is the larger problem to the small portion that I already posted in the Precalc Hw help forum. I still can't figure out how to get to the answer.

The problem is this:
I am trying to find the derivative of f(x)=x+\frac{9}{x}.

Homework Equations


I know via power rule that the answer will be:
\frac{dy}{dx}=1+\frac{9}{x^{2}}
However, I must do it the messy way.

The Attempt at a Solution


This is what I have got so far:
1.\frac{f(x+h)-f(x)}{h}

2.=\lim_{h\rightarrow0}\frac{\left((x+h)+\frac{9}{x+h}\right)-\left(x+\frac{9}{x}\right)}{h}

3.=\lim_{h\rightarrow0}\frac{x+h+\frac{9}{x+h}-x-\frac{9}{x}}{h}

4.=\lim_{h\rightarrow0}\frac{h}{h}+\frac{\frac{9}{x+h}}{h}-\frac{\frac{9}{x}}{h}

5.=\lim_{h\rightarrow0}1+\left(\frac{9h}{x+h}-\frac{9h}{x}\right)

6.=\lim_{h\rightarrow0}1+\left(\frac{x}{x}\cdot\frac{9h}{x+h}-\frac{9h}{x}\cdot\frac{x+h}{x+h}\right)

7.=\lim_{h\rightarrow0}1+\frac{9hx-9hx-9h^{2}}{x(x+h)}

8.=\lim_{h\rightarrow0}1+\frac{-9h^{2}}{x(x+h)}

I don't know where to go from here or even if here is where I am supposed to be. Help please?
 
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Feldoh said:
Partial fraction decomposition might work.

Partial whos-a-what? :confused:
 
efekwulsemmay said:
Partial whos-a-what? :confused:

You were doing fine until step 5. Then you changed (9/(x+h)-9/x)/h into (9h/(x+h)-9h/x). You can't do that. You just moved h into the numerator by 'magic'. Leave it in the denominator! You also don't want to multiply by h/h in the next step. You want to multiply by x/x to get the common denominator.
 
Dick said:
You also don't want to multiply by h/h in the next step. You want to multiply by x/x to get the common denominator.

Ok that's where I went wrong. Thanks for your help. :biggrin: Btw the multiplying h/h was a typo, its supposed to be x/x.
 
Awesome. So going by what you said Dick, I figured out that I messed up by putting that h in the numerator (slopy fraction solving :) ) I worked it out and got the right answer. Thanks for your help Dick.
 
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