Setting Up a Matrix with Order Unity Elements: A Scientist's Guide

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Homework Statement


A determinant with all elements of order unity may be surprisingly small. The Gilbert determinant Hij=(I+j-1)^-1, i,j=2... n is notorious for its small values.

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The Attempt at a Solution


I just need help setting up the matrix and I can solve it myself. Thanks
 
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I know how to find the numbers for the matrix but I'm confused as to how big the matrix is supposed to be. Am I doing a 1 by 1 then a 2 by 2 then a 3 by3 or am I doing a 3 by 3
 
Your notation is a little unclear to me. I assume i represents the matrix row and j represents the matrix column. If that equation is ##H_{ij} = (i+j-1)^{-1}## with dimension equal to 2, then the value of each element is given by this equation with whichever row and column number plugged in.
 
Ashley1nOnly said:
I know how to find the numbers for the matrix but I'm confused as to how big the matrix is supposed to be. Am I doing a 1 by 1 then a 2 by 2 then a 3 by3 or am I doing a 3 by 3

Your problem statement doesn't give any direction for actually solving anything. Is there more to it?
 
Yes sorry. I'm stuck on the part where it says by order of n=1,2, and 3. What is is asking me to do?. I have already found my matrix using the given equation( it repeats itself in a decreasing way)
 
Calculate the value of the Hoover determinant of order n for n=1,2, and 3.

Is the problem
 
If it tells you to solve for an order of 1, 2, and 3, then it's telling you to compute the determinant of a 1x1, 2x2, and 3x3 matrix.
 
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Quick question. When you are finding the determinant of a matrix. Do the rows and columns have to be equal?
 
Ashley1nOnly said:
Quick question. When you are finding the determinant of a matrix. Do the rows and columns have to be equal?

Yes. You can only take the determinant of a square matrix.
 
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For my answers I got
1
1/12
And I am working on the third
 
  • #11
For the 3 by 3
0.00046297
 
  • #12
That looks right!
 
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