How do I simplify Boolean simplification ABC + AB' . ( A' C') + A'BC?

  • Thread starter Thread starter adnankhuram
  • Start date Start date
AI Thread Summary
The discussion focuses on simplifying the Boolean expression ABC + AB' . (A' C') + A'BC. Participants express confusion about the multiplication of AB' and (A' C'), leading to the realization that AA' equals zero, which simplifies the expression. The simplification process reveals that the second term cancels out, resulting in the expression reducing to ABC + A'BC. Further simplification leads to the conclusion that the expression can be factored to BC(A + A'), ultimately simplifying to BC. The conversation emphasizes the importance of recognizing terms that cancel out in Boolean algebra.
adnankhuram
Messages
3
Reaction score
0
ABC + AB' . ( A' C') + A'BC

I am confused in AB' . ( A' C')

the multiplication would be AA'B'C' OR AA'C'+A'B'C'
 
Physics news on Phys.org
adnankhuram said:
ABC + AB' . ( A' C') + A'BC

I am confused in AB' . ( A' C')

the multiplication would be AA'B'C' OR AA'C'+A'B'C'

It is AA'B'C'.

ehild
 
Abc + ab' . ( a' c') + a'bc

abc + aa'b'c' + a'bc

abc + b'c' + a'bc ( aa' = 0)

bc(a + b'c' +a')

bc (a+a'+b'c') as a+a' = 1

bc( b'c')

bb'cc'

0

is this is right
 
adnankhuram said:
Abc + ab' . ( a' c') + a'bc

abc + aa'b'c' + a'bc

abc + b'c' + a'bc ( aa' = 0)

As aa'=0 the second term cancels. You have abc+a'bc. Continue from here.

ehild
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
View full post »

Thread 'Struggling to understand the concept of this question (ice cube in water optics question)'

TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
View full post »

Similar threads

Did I Simplify These Boolean Expressions Correctly?
Replies
2
Views
2K
How do I calculate the Tension in a rope going over a smooth pulley?
Replies
19
Views
1K
Engineering Where Did the Minterm AB'C Come From in This Boolean Function?
Replies
5
Views
2K
Boolean Algebra Simplification Help
Replies
3
Views
3K
How Can Boolean Algebra Simplification Be Achieved?
Replies
14
Views
4K
Is my textbook wrong about absolute uncertainties?
Replies
2
Views
1K
A moving boat with a flag on its mast
Replies
15
Views
969
Verifying that Newton's Equations are equivalent to the EL equations
Replies
15
Views
1K
MHB Simplify a+b+c+d+2(ab+ac+ad+bc+bd+cd)+4(abc+abd+acd+bcd)+8(abcd)
Replies
3
Views
2K
Reduction of Boolean Expression to its Lowest From
Replies
5
Views
2K

Hot Threads

Recent Insights

Back
Top