How Do Phase Shifts Affect Resultant Wave Amplitude and Frequency?

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SUMMARY

The discussion focuses on the calculation of the resultant wave amplitude and frequency from two sinusoidal waves described by the functions y1 = (5.00m) sin[π(4.00x - 1200t)] and y2 = (5.00m) sin[π(4.00x - 1200t - 0.250)]. The amplitude of the resultant wave is determined to be approximately 10m using the formula A = (2A cos(Φ/2)), where Φ represents the phase difference. The frequency remains consistent with the original waves at 1200 Hz, as the phase shift does not alter the frequency of the waves.

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Homework Statement


Two traveling sinusoidal waves are described by the wave functions
y1 = (5.00m) sin[pie(4.00x - 1 200t)]
y2 = (5.00m) sin[pie(4.00x - 1 200t -0.250y)]
where x, y1, and y2 are in meters and t is in seconds.
(a) What s the amplitude of the resultant wave?
(b) What is the frequency of the resultant wave?


Homework Equations


y = (2Acos Phi/2) sin(kx- wt + Phi/2)


The Attempt at a Solution


The two waves are out of phase by 0.250
therefore A = (2A cos Phi/2)
I get the Amplitude to be 9.99 or 10m
from 2 (5.00m) .25/2
Do I need to do more for this? I know the answer but can't get there
Thanks,
Kevin
 
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Husker70 said:

Homework Statement


Two traveling sinusoidal waves are described by the wave functions
y1 = (5.00m) sin[pie(4.00x - 1 200t)]
y2 = (5.00m) sin[pie(4.00x - 1 200t -0.250y)]
where x, y1, and y2 are in meters and t is in seconds.
Is it "-0.250y" or just "-0.250" for the phase in y2?

(a) What s the amplitude of the resultant wave?
(b) What is the frequency of the resultant wave?


Homework Equations


y = (2Acos Phi/2) sin(kx- wt + Phi/2)


The Attempt at a Solution


The two waves are out of phase by 0.250
therefore A = (2A cos Phi/2)
I get the Amplitude to be 9.99 or 10m
It should be slightly lower. Was your calculator in radians mode when you calculated cos(0.25)?

from 2 (5.00m) .25/2
Do I need to do more for this? I know the answer but can't get there
Thanks,
Kevin
 

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