How Do Plastic Sheets Affect Young's Interference Pattern?

AI Thread Summary
The discussion focuses on an experiment involving Young's interference pattern, where two thin plastic sheets with a refractive index of 1.50 are placed in front of two slits. The student seeks to understand how these sheets affect the interference pattern and the distance between maxima. They express difficulty in applying the correct formulas for two slits, having previously only worked with single slit interference. Clarification is sought on calculating the effective path length difference due to the plastic sheets. The conversation emphasizes the importance of understanding the relationship between the materials used and the resulting interference effects.
YoungILoveYou
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Hello, I' m an italian student, so exscuse for my bad english.
My problem:
A device for the experiment of the two splits of Young is considered in which the distance between the splits it is d=0.30mm and the distance from the screen is L=1m. Two thin transparent plastic sheets (n=1.50) of thickness 0.050mm and 0.025mm are placed dinanzi to the advanced and inferior split respective. To discuss like modification the figure of interference observed on the screen and the distance between two max of interference.
 
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Hi Young,

What have you done with this problem so far? Have you tried to calculate the effective difference in the path length? If you share your thoughts/ideas in this problem, it will be easier for us to help.

Also, what's "dinanzi"? Is it an Italian word?
 
Ehm, yes,some trouble with google translator :)
"dinanzi"= in front

If you want, edit my first message. Thanks

My problem is that I do not succeed to take advantage of the various measures of two slits.Usuallly I have only worked with one interference slit.

I creed that in reality is from only using one formula like this:

2nd=(m + 1/2) \lambda

where
lambda is the distance, n=1.50, d= thickness of slit ad m=0,1,2..
 
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