How Do Plastic Sheets Affect Young's Interference Pattern?

YoungILoveYou
Messages
10
Reaction score
0
Hello, I' m an italian student, so exscuse for my bad english.
My problem:
A device for the experiment of the two splits of Young is considered in which the distance between the splits it is d=0.30mm and the distance from the screen is L=1m. Two thin transparent plastic sheets (n=1.50) of thickness 0.050mm and 0.025mm are placed dinanzi to the advanced and inferior split respective. To discuss like modification the figure of interference observed on the screen and the distance between two max of interference.
 
Physics news on Phys.org
Hi Young,

What have you done with this problem so far? Have you tried to calculate the effective difference in the path length? If you share your thoughts/ideas in this problem, it will be easier for us to help.

Also, what's "dinanzi"? Is it an Italian word?
 
Ehm, yes,some trouble with google translator :)
"dinanzi"= in front

If you want, edit my first message. Thanks

My problem is that I do not succeed to take advantage of the various measures of two slits.Usuallly I have only worked with one interference slit.

I creed that in reality is from only using one formula like this:

2nd=(m + 1/2) \lambda

where
lambda is the distance, n=1.50, d= thickness of slit ad m=0,1,2..
 
To solve this, I first used the units to work out that a= m* a/m, i.e. t=z/λ. This would allow you to determine the time duration within an interval section by section and then add this to the previous ones to obtain the age of the respective layer. However, this would require a constant thickness per year for each interval. However, since this is most likely not the case, my next consideration was that the age must be the integral of a 1/λ(z) function, which I cannot model.
Back
Top