How Do Point Charges Affect Electric Field Vectors at a Specific Location?

AI Thread Summary
The discussion focuses on calculating the electric fields E1 and E2 at point P due to two point charges, q1 and q2, located at specified coordinates. The calculations for E1 and E2 are derived using the electric field formula and unit vectors, with E1 resulting in a negative j-component and E2 yielding a positive i-component. There is confusion regarding the placement of q2 on the x-axis, specifically whether it is at +3 cm or -3 cm, which affects the direction of the electric field vectors. The participant expresses uncertainty about their calculations, despite following the textbook steps. Clarification on the position of q2 is crucial for resolving the discrepancies in the electric field vector components.
sami23
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Homework Statement


Point charge q1= -5.00 is at the origin and point charge q2= +3.00 is on the -x axis at x= 3.00 cm. Point P is on the y-axis at y= 4.00 cm .

Calculate the electric fields E1 and E2 at point P due to the charges q1 and q2. Express your results in terms of unit vectors.


Homework Equations



r = sqrt(x2 + y2)
hat{r} = (vec{r} /r = x hat{i} + y hat{j}) / r
vec{E} = (k * q)/r2 hat{r}


The Attempt at a Solution


E1 will be the vector from q1 to point P
r = sqrt(02 + .042) = .04 m

hat{r} = (0 hat{i} + .04 hat{j})/.04 = 0 hat{i} + 1 hat{j}

E1 = (9*109) * (-5.00*10-9) / .042 (0 hat{i} + 1 hat{j})
= 0 hat{i} - 2.81*104 hat{j}

i did the exact same steps to find E2 and
E2 = 6.47*102 hat{i} + 8.62*102 hat{j}

Am I doing something wrong? According to the steps I used because my answers are wrong and i even followed the way the steps were in the book.
 
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Is q2 at x = +3 cm or at x = -3 cm?
 
q2 is at x=+3 cm = 0.03m
 
sami23 said:
q2 is at x=+3 cm = 0.03m
So how did you end up with a positive i-component?
 
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