How Do Transition Wavelengths Compare Between Hydrogen and Helium?

Shackleford
Messages
1,649
Reaction score
2
6.

http://i111.photobucket.com/albums/n149/camarolt4z28/2010-09-23195548.jpg?t=1285299756

I'm thinking I use the omegaij formula to determine the frequency between energy levels and then use that to calculate the wavelength.

http://i111.photobucket.com/albums/n149/camarolt4z28/2010-09-23195519.jpg?t=1285299772

http://i111.photobucket.com/albums/n149/camarolt4z28/2010-09-23194832.jpg?t=1285299825
 
Last edited by a moderator:
Physics news on Phys.org
sounds good.
 
zhermes said:
sounds good.

Well, I must be doing something computationally incorrectly.

For (1) hydrogen, I'm getting a wavelength of 1.93 x 10^-8 m or 19.3 nm.
 
Any bright ideas? lol.
 
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...
Back
Top