How Do Two Balls Dropped from a Window Hit the Ground Simultaneously?

  • Thread starter Thread starter mike_302
  • Start date Start date
  • Tags Tags
    Gravity
AI Thread Summary
A ball is thrown upward from a 3.6 m high window with an initial speed of 2.8 m/s, hitting the ground at -8.86 m/s. To determine when a second ball should be dropped so both hit the ground simultaneously, the equations of motion for both balls must be set up. The first ball's motion includes an initial velocity term, while the second ball's motion starts from rest. The key is to solve for the time variables separately and find the difference between them. This approach will yield the time delay needed for the second ball to ensure both impact the ground at the same moment.
mike_302
Messages
102
Reaction score
0

Homework Statement


A ball is thrown vertically upward from a window that is 3.6 m above the ground. Its initial speed is 2.8 m/s .

(a)with what speed does the ball hit hte ground?
(b)How long after the first ball is thrown, should a second ball be simply dropped from the same window, so that they both hit the ground at the same time?


Homework Equations



any of the 5 uniform acceleration equations. Gravity is -9.81 (he insists on the 1)


The Attempt at a Solution



I have (a) done... I obtained -8.86 m/s as the velocity when it hits the ground. But for (b), I don't know what method to go about doing this. My gut says there might be something easy, applying the "final speed" that I obtained in (a), but we also learned yesterday to do some graphing methods... Determine when two objects hit the same position, going at this velocity, and the other going at this velocity... That's what I'm trying to do here, but I can't figure it out.

For the dropped ball, the equation would be 0=1/2(-9.81)DeltaT^2 (from d2=v1DeltaT + 1/2aDeltaT^2 + d1 )

But what about the other ball?
 
Physics news on Phys.org
The equation for the other ball would be the same except with a Vi*t term added.
Careful - the T's in the two equations are different. Better use t1 and t2 or something.
Solve each equation so you know t1 and t2. The difference is the answer!
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top