courtrigrad
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Hello all
Let's say we have \frac{1}{\sqrt{2\pi}} e^{\frac{-1}{2\phi^2}} where \phi is a standarized normal variable. Let R_{i} = \frac{S_{i+1} - S_{i}}{S_{i}}Also let's say we have a time step \delta t and the mean of the returns scaled with the timestep.Then mean = \mu\delta t
Then why does \frac{S_{i+1}-S_{i}}{S_{i}} = \mu\delta t? Isn't this supposed to be a z-score? Also suppose we want to know how the standard deviation scales with the timestep \delta t The sample standard deviation is \sqrt{\frac{1}{M-1}\sum^M_{i=1}(R_{i}-R)^2} How do we use this to get standard deviation = \sigma\delta t^{\frac{1}{2}}
Also why does R_{i} = \mu\delta t + \sigma\phi\delta t ^{\frac{1}{2}}?
Thanks
Let's say we have \frac{1}{\sqrt{2\pi}} e^{\frac{-1}{2\phi^2}} where \phi is a standarized normal variable. Let R_{i} = \frac{S_{i+1} - S_{i}}{S_{i}}Also let's say we have a time step \delta t and the mean of the returns scaled with the timestep.Then mean = \mu\delta t
Then why does \frac{S_{i+1}-S_{i}}{S_{i}} = \mu\delta t? Isn't this supposed to be a z-score? Also suppose we want to know how the standard deviation scales with the timestep \delta t The sample standard deviation is \sqrt{\frac{1}{M-1}\sum^M_{i=1}(R_{i}-R)^2} How do we use this to get standard deviation = \sigma\delta t^{\frac{1}{2}}
Also why does R_{i} = \mu\delta t + \sigma\phi\delta t ^{\frac{1}{2}}?
Thanks

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