How Do You Apply the Quotient Rule to Differentiate (x-1)^2/(x+1)^2?

Nitrate
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Homework Statement


a) Differentiate y=((x-1)/(x+1))^2

b (non calculus simplification question):
How would i simplify 10(5x+3)(5x-1)+5(5x-1)^2 to get 25(5x-1)(3x+1)
should i expand all terms then combine and factor?



Homework Equations





The Attempt at a Solution


a) i tried using the quotient rule but kept ending up with missing terms...
from the answer key i know that the answer is (4(x-1))/(x+1)^3
but i can't get that for the life of me...
 
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Chain rule on this simplifies it a lot.. (if you know it?)

y=u^{2}

u=\frac{x-1}{x+1}


EDIT: Just in case you don't knnow, take the derivative of y and u then do the following:

\frac{dy}{dx}=\frac{dy}{du}\cdot\frac{du}{dx}
 
Last edited:


iRaid said:
Chain rule on this simplifies it a lot.. (if you know it?)

y=u^{2}

u=\frac{x-1}{x+1}

i do
however I've never really learned it using substitutions.
would i bring up the (x+1)^2 to the top, so that the equation becomes (x-1)^2(x+1)^-2?
or would that further complicate things
 


Nitrate said:
i do
however I've never really learned it using substitutions.
would i bring up the (x+1)^2 to the top, so that the equation becomes (x-1)^2(x+1)^-2?
or would that further complicate things

I editted my post, maybe that will help you
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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