How Do You Apply Trigonometric Substitution to Integrate Sqrt(X^2 + 9)?

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Homework Statement


Evaluate the Integral: Sqrt[(X^2)+9]

Homework Equations


I know its an Integration By parts problem, but I don't know how to start it.


The Attempt at a Solution



Im JUST learning this as I type this problem out, I've just been stuck on it for a while and my book does a horrible job of explaining how to do problems. If anybody could explain the Trigonometric substitution technique or knows of a good website that explains it I would be very grateful.

For this problem though, all I did was set x=3sin(u) and dx=3cos(u).

I don't know if that's right though, because like I said, I just "learned" this yesterday
 
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Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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