How Do You Calculate a Ship's Velocity Given Its Direction and Displacement?

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To calculate a ship's velocity given its direction and displacement, first identify the components of the velocity vector based on the ship's heading of 55 degrees west of north. The ship travels 65 km north in 3 hours, allowing for the determination of the northward component of its velocity. By applying trigonometry, the northward and westward components can be represented in a right triangle, with the hypotenuse indicating the total velocity magnitude. The problem emphasizes the importance of understanding vector components to solve for the ship's overall velocity. This approach combines geometry and trigonometric principles to derive the solution effectively.
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Homework Statement



A ship traveling 55 degrees [W of N] is 65.0 km farther north after 3.0 h. What is the ship's velocity?

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The Attempt at a Solution



I am totally not sure how to start this problem. My teacher told me there are two type of problems, AIM or Drift. I think this problem is AIM. I know then I have to draw the resultant first.
 
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Below said:

Homework Statement



A ship traveling 55 degrees [W of N] is 65.0 km farther north after 3.0 h. What is the ship's velocity?

This is a problem involving components of the velocity vector. Draw the direction of the velocity vector, which points 55º west of north. Then draw its northward and westward components so that you've formed a right triangle.

You are told that the ship is 65 km farther north after 3 hours, so what is the northward component of the ship's velocity (the speed in the northerly direction)? How can you use trigonometry to find the length of the hypotenuse of this triangle, which represents the total magnitude of the ship's velocity? (You already know the direction.)
 
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