How Do You Calculate Acceleration with Friction Involved?

AI Thread Summary
To calculate the acceleration of a crate being pushed with friction, first determine the net force acting on it. The applied force is 280 N, and the frictional force is 118.44 N, resulting in a net force of 161.56 N. Using Newton's second law, acceleration can be calculated with the formula a = F/m, where F is the net force and m is the mass of the crate. Substituting the values gives a = 161.56 N / 40 kg, resulting in an acceleration of 4.04 m/s². This approach effectively incorporates the effects of friction in the acceleration calculation.
bship810
Messages
2
Reaction score
0

Homework Statement


A person pushes horizontally with a force of 280 N on a 40 kg crate to move it across a level floor. The coefficient of kinetic friction is 0.30. the magnitude of the frictional force is 118.44. What is the magnitude of the crate's acceleration?



Homework Equations


Fn=ma
fk=uk*Fn


The Attempt at a Solution


I figured out the first problem which was finding the magnitude of frictional force. I think I have to take 280N-118.44N for some reason. Thats just a gut feeling though.

Im just not totally sure which equations to use and what order to use them

Help would be great
 
Physics news on Phys.org
Don't just guess. Draw a picture. In which directions are the two horizontal forces applied to the crate?
 
ok, so the frictional force is countering the person's force. that would mean there is a 161.56N force still remaining pushing the box forward.

How do get acceleration from this? a=Fn/m? so that would give me" a=(161.56)/(40). thus a=4.04. is this right?
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top