How Do You Calculate Buoyant Force on an Iceberg?

AI Thread Summary
To calculate the buoyant force on an iceberg, first determine the volume of the submerged part by multiplying the iceberg's cross-sectional area (3.10x10^4 km^2) by the submerged depth (0.84 km). The buoyant force is equal to the weight of the displaced water, which can be calculated using the formula: buoyant force = volume of water displaced × density of water (1.035x10^3 kg/m^3). The discussion highlights that the problem can be simplified by focusing on the volume of the submerged iceberg rather than overcomplicating the calculations. Overall, understanding the relationship between the submerged volume and the density of the fluid is key to solving the problem effectively.
Milad_1989
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Homework Statement



Iceberg area: 3.10x10^4 km^2, Flat top and bottom.
Submerged part .84 km.
Water density: 1.035x10^3

what is the buoyant force acting on the iceberg?

Homework Equations



Fb=Fg pf object of subject = P0V0g
PfVfg=Weight of displaced fluid=p0v0g=weight of object
Vu=v0-vf=v0-(p0v0g/pfg)=v0(1-(po/pf)

I have spend now over 2 hours trying to solve this problem, but no success... Can any help me solve it... driving me crazy..
Thanks in advance..
 
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Milad_1989 said:

Homework Statement



Iceberg area: 3.10x10^4 km^2, Flat top and bottom.
Submerged part .84 km.
Water density: 1.035x10^3

what is the buoyant force acting on the iceberg?

Homework Equations



Fb=Fg pf object of subject = P0V0g
PfVfg=Weight of displaced fluid=p0v0g=weight of object
Vu=v0-vf=v0-(p0v0g/pfg)=v0(1-(po/pf)

I have spend now over 2 hours trying to solve this problem, but no success... Can any help me solve it... driving me crazy..
Thanks in advance..

If the area you mentioned is the area of cross section of the iceberg. Assuming that the iceberg has uniform shape, the volume of iceberg submerged= Iceberg area*Submerged part
the volume of water displaced will be=volume of iceberg submerged= Iceberg area*Submerged part

Buoyant force acting on it=Weight of water displaced=Volume of water displaced*density of water

I wonder if it helps!
 
Thanks, I was over-thinking it and i cannot believe it is so simple.
 

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