How Do You Calculate Current Density Between Coaxial Cylinders?

AI Thread Summary
To calculate the current density J(r) between coaxial cylinders, the resistance of the dielectric is determined as ln(b/a)/(2πLσ), leading to the equation for current as I = V/R. The first approach yields J(r) = Voσ/(r ln(r/a)), while the second method incorporates the dielectric constant, resulting in J(r) = σVoε/(r ln(b/a)). The key difference between the two methods is the inclusion of ε in the second approach. Ultimately, the consensus leans towards the first method as the more straightforward solution for calculating current density.
RyanP
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Homework Statement


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Two long, coaxial metal cylinders are separated by a material of conductivity sigma and dielectric constant epsilon. The radius of the inner cylinder is a, the radius of outer cylinder is b, and the length of both is L.

Suppose that the inner conductor is held at a potential Vo with respect to the outer one. What is the current density J(r) between the two?

Homework Equations


J(r) = I/A = sigma*E
C=Q/V
R=s/(A*sigma)

The Attempt at a Solution


First attempt:
I found resistance of the dielectric to be ln(b/a)/(2pi*L*sigma). As a function of radius r, R(r) = ln(r/a)/(2pi*L*sigma).

Current = V/R = Vo / (ln(b/a)/(2piLsigma)) = Vo*2pi*L*sigma / ln(r/a) as a function of r.
Then divide by Area=2pi*L*r to get current density J(r) = Vo*sigma / (r*ln(r/a)). Second attempt:
Vo = Q/C. I found capacitance of the configuration to be 2pi*epsilon_o*L*epsilon / ln(b/a) using the expression for resistance. Then Q = Vo*2pi*L*epsilon*epsilon_o / ln(b/a).
EA = Q/epsilon_o, so E = Vo*epsilon / (r*ln(b/a)). Using J(r) = E*sigma, I get J(r) = sigma*Vo*epsilon / rln(b/a).

The difference in the two is the presence of epsilon (dielectric constant) in the numerator, and b rather than r in the ln term of the denominator. Are either of these approaches correct?
 
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Can bound charges support current flow?
Better stick with method 1.
 
RyanP said:
Current = V/R = Vo / (ln(b/a)/(2piLsigma))
Looks reasonable (but I've not checked it in detail).
RyanP said:
= Vo*2pi*L*sigma / ln(r/a) as a function of r.
That I don't understand. The same total current has to flow through any given radius, no?
 
Ok, maybe instead I'll do J(r) = current (constant) / area (function of r). In this case I just get J(r) = V*sigma/(r*ln(b/a)). Does this sound right?
 
RyanP said:
Ok, maybe instead I'll do J(r) = current (constant) / area (function of r). In this case I just get J(r) = V*sigma/(r*ln(b/a)). Does this sound right?
Sounds right, looks right ... I'm buying!
 
RyanP said:
Ok, maybe instead I'll do J(r) = current (constant) / area (function of r). In this case I just get J(r) = V*sigma/(r*ln(b/a)). Does this sound right?
Looks right to me too.
 
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