How Do You Calculate Initial Velocity from Jump Height?

  • Thread starter Thread starter btr94
  • Start date Start date
  • Tags Tags
    Forces
AI Thread Summary
To calculate the initial velocity of a jumper from jump height, the peak height of 140 cm and the standing hip position of 100 cm are essential variables. The problem involves understanding the transition from potential energy (PE) at peak height to kinetic energy (KE) just after takeoff. The relevant equations include PE = 1/2kx^2 and KE = 1/2mv^2, although time measurements are not provided. The challenge lies in applying these formulas without direct time data. Ultimately, the solution requires relating the height difference to the initial velocity using energy conservation principles.
btr94
Messages
1
Reaction score
0

Homework Statement


Standing position: 100cm
Lowered hip position: 77cm
Peak height: 140cm

Question "Use the peak height of the jump and the standing hip position to calculate the initial velocity of the jumper just after he left the ground"


Homework Equations


Unknown


The Attempt at a Solution


Unknown - I only know equations that require time. I know no time measurement in this problem.

The problem is a jumping problem. The variable above, in order, are:
1. Standing tall - from the floor to the hip
2. Crouched down to jump - from the floor to the hip
3. In mid-air at the peak of the jump - from the floor to the hip.

These were measured using a 2-meter stick.
 
Physics news on Phys.org
You need to use the force formulas:

PE spring = 1/2kx^2
KE = 1/2mv^2
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top