How Do You Calculate the Acceleration of an Electron in a Magnetic Field?

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To calculate the acceleration of an electron in a magnetic field, the force can be determined using the formula F=qvB, resulting in a force of 1.2 x 10^-12 N. The mass of an electron is approximately 9.109 x 10^-31 kg. Using Newton's second law, acceleration can be calculated as a = F/m, leading to a value of 1.32 x 10^18 m/s^2. A previous calculation yielded an incorrect acceleration of 7.6 x 10^-19 m/s^2. The discrepancy highlights the importance of correctly applying the formulas and values.
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An electron has a velocity of 5 x 10^6 m / s perpendicular to a magnetic field of 1.5 T. What force and acceleration does the elcetron experience?

ok i get the Force part by using F=qvB, how do i get the Acceleration?

F= 1.2x10^-12 N A= ?
 
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Remember Newton's second law? F=ma, F is force, m is mass, a is acceleration.
 
d_leet said:
Remember Newton's second law? F=ma, F is force, m is mass, a is acceleration.


i know this but how do i get the acceleration when i don't have the mass of the electron?
 
tnkfub said:
i know this but how do i get the acceleration when i don't have the mass of the electron?

electron mass = 9.10938188 × 10^-31 kilograms

All electrons have approx. the same mass.
 
ranger said:
electron mass = 9.10938188 × 10^-31 kilograms

All electrons have approx. the same mass.


f=ma, a = m/f , a = 9.1x10^-31 / 1.2x10^-12 = 7.6 x 10 - 19

the answer according to the back of the textbook is way different a = 1.32x10^18m/s^2

maybe the answer is wrong? in the book
 
Last edited:
tnkfub said:
f=ma, a = m/f , a = 9.1x10^-31 / 1.2x10^-12 = 7.6 x 10 - 19

the answer according to the back of the textbook is way different a = 1.32x10^18m/s^2


You solved for acceleration incorrectly.
 
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