How Do You Calculate the Density of a Body and a Liquid Based on Buoyancy?

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To calculate the density of a body and a liquid based on buoyancy, the weights of the body in air, water, and another liquid are essential. The body weighs 7.55 kg in air, 5.17 kg in water, and 6.35 kg in a certain liquid, with the density of water given as 1000 kg/m^3. The discussion highlights the need to clarify whether the provided values are weights in Newtons or masses in kilograms. Using the buoyant force and the principle of Archimedes, the densities can be derived from the weight differences in various mediums. Accurate calculations depend on understanding the correct units for weight and mass.
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A Body Weight 7.55kg in air 5.17kg in water and 6.35kg in a certain liquid. Find the Density of the body and that of the liquid if Density of water is 1000 kg/m^3




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Weights aren't measured in kilograms. Are those values you gave supposed to be the weights, measured in Newtons, or, are the masses, measured in kilograms?
 
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Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...

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