How Do You Calculate the Distance Between Two Slits in a Double Slit Experiment?

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Homework Help Overview

The discussion revolves around a double slit experiment involving light of 650 nm and the calculation of the distance between two slits based on observed angles for maxima and minima. Participants are attempting to determine the order of the maximum and the slit separation.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss using equations for constructive and destructive interference to find the distance between the slits and the order of the maximum. There are attempts to manipulate the equations to isolate variables, and some participants express uncertainty about their mathematical processes.

Discussion Status

Several participants have shared their calculations and results, noting discrepancies in their values for the order of the maximum. There is an ongoing exploration of the mathematical relationships involved, with some guidance being offered on how to approach the problem.

Contextual Notes

Participants mention challenges with the chapter and express gratitude for assistance, indicating a collaborative effort to understand the concepts involved.

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Homework Statement



Light of 650 nm is incident on two slits. A maximum is seen at an angle of 10.93degrees and a minimum of 11.73degrees. What is the order m of the maximum?

What is the distance d between the slits?

Homework Equations



dsin(theta)=m(lambda) - max

dsin(theta)=(m+1/2)(lambda - min

The Attempt at a Solution



So I started out with the two equations, one for the constructive interference and destructive interference. I solved one equation for d, and then substituted that solved equation into the other to try and find m. I don't know if it was an error in math or what, but I can't seem to solve this problem. Is there an easier way that this, or is this the easiest?

P.S. Sorry I've posted three threads for three different questions, but I'm having trouble with this chapter. Thank you for your patience and your help.
 
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It sounds good to me. I wrote the two equations
mL = d*sin(A) and (m+.5)L = d*sin(B) and divided them to eliminate the d.
This almost resulted in a whole number - one % off. Close enough, I guess.
 
What did you get for your m? I took an m out after I divided the two equations, so it looked like m=(.5sinA)/sinB, which got me about .466330. I tried entering it and it wasn't right. My math is definitely wrong ._.
 
Dividing the 2 equations, I got
1 + .5/m = sin(B)/sin(A) = 1.072203
so .5/m = .072203
m = 6.92
 
That explains what I did wrong. I figured it out. Thanks for all your help Delphi!
 
Woohoo
 

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