How Do You Calculate the Equivalent Resistance in Complex Resistor Networks?

AI Thread Summary
To calculate the equivalent resistance in complex resistor networks, one can use series and parallel relationships, but the specific configuration can complicate the process. The problem presented involves a network where the expected equivalent resistance is 27/17, yet the solver struggles to reach this answer despite close attempts. A suggested method is to apply Kirchhoff's Current Law (KCL) by reorienting the circuit and analyzing the voltages and currents at the nodes. This brute-force approach, while effective, may not be the simplest solution available. The discussion emphasizes the need for clarity in complex resistor configurations and encourages sharing any simpler methods discovered.
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Homework Statement



This problem involves a sketch of a system of resistors, so I will do my best.

A--xx1xx---|---xx1xx--B
.\.....|..../
...x...x...x
...x...x...x
...3...1...5
...x...x...x
...x...x...x
...\...|.../
.....\.|./
...\/

The numbers between the x's represent the resistors and their vaules.

The question asks to find the equivalent resistance R[ab].

Homework Equations



I am aware of the series/parallel relation ships between resistors, but this question seems ambiguous.

1/Req = 1/R1 + 1/R2
Req = R1 + R2

The Attempt at a Solution



The question states that the solution should be 27/17, but anyway I work this problem I dno't seem to get this answer, although I have gotten very close.

Any help?
 
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I don't see a simplification right off the bat (there may be one I'm missing), so what I would do is just solve the circuit using the KCL technique, and convert the answer into an overall resistance.

Like, turn the circuit 90 degrees clockwise, so A is on the top, and B is on the bottom. Ground B and put 1V in at A. Now write the two KCL equations for the voltages at the unknown nodes and solve for those voltages. That will give you the currents and voltages, so sum the currents through the two resistors leading out of A, and that along with the one 1V in will give you the overall resistance.

I often lose patience with these kind of problems early, and just do it the brute force way. BTW, if you find out that there's a simpler way to do it, please post it so I can learn it.
 
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