How Do You Calculate the Force Needed to Accelerate an Electron?

  • Thread starter Thread starter crimsonn
  • Start date Start date
  • Tags Tags
    Kinetic
AI Thread Summary
To calculate the force needed to accelerate an electron, the work-energy theorem is applied, using the equations W = Fd and KE = 1/2mv^2. The problem involves accelerating an electron (mass 9.11 x 10^-31 kg) from an initial speed of 1.50 x 10^7 m/s over a distance of 0.0125 meters. The attempted solution incorrectly applied the equations, leading to confusion about the initial conditions and final speed. Clarification is needed regarding whether the electron starts from rest and the specific final speed intended for the calculation. The correct answer for the force required is 3.56 x 10^-19 N.
crimsonn
Messages
28
Reaction score
0

Homework Statement



use the work energy theorem to find the force required to accelerate an electron (m=9.11 X10^-31 kg) from a speed of 1.50 X10^7 m/s in a distance of .0125

Homework Equations


W=Fd KE= 1/2mv^2

W=KE


The Attempt at a Solution



I've tried this problem about eight times, and each time I managed to get a different answer, but this is my try at a solution

W=Fx
W/x= F

W=1/2mv^2

mv^2/2x = F

however, this does not work for me.

the answer is 3.56 X10 -19N
 
Physics news on Phys.org
crimsonn said:

Homework Statement



use the work energy theorem to find the force required to accelerate an electron (m=9.11 X10^-31 kg) from a speed of 1.50 X10^7 m/s in a distance of .0125

[...]

To a speed of what? What is the unit of distance?
 
Yeah, was this electron at rest to begin with, or was it in motion already? Check the wording of your question.
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top