How Do You Calculate the Frictional and Coupling Forces for a Skidding Truck?

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To calculate the frictional and coupling forces for a skidding truck, one must first determine the deceleration using the equation v² = v₀² + 2a(s - s₀). After calculating the deceleration, free body diagrams for both the truck and trailer should be drawn to apply F = ma. The forces acting on the truck and trailer lead to values of -11.25 kN for the trailer and -22.5 kN for the truck, with the coupling force calculated as FC = -11.25 kN. The coefficient of friction (µ) can be assumed based on the surface, but it's noted that the forces can be derived from mass and acceleration without it. Understanding the dynamics of the system is crucial for accurate force calculations.
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1.The 2-Mg truck is traveling at 15 m/s when the brakes
on all its wheels are applied, causing it to skid for a distance of
10 m before coming to rest. Determine the constant horizontal
force developed in the coupling C, and the frictional force
developed between the tires of the truck and the road during
this time. The total mass of the boat and trailer is 1 Mg.


v0 = 15 m/s
s = 10 m
Fk = µkN

2. I'm not exactly sure how/where to start. I also have no idea how to get the frictional force.



The Attempt at a Solution


I figure that since I know v0 and vf as well as s0 and sf that I can get deceleration.

I'll use v2 = v02 + 2a(s-s0). If I solve for a, maybe that will help get the frictional force?
 
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welcome to pf!

hi winblowzxp! welcome to pf! :wink:
winblowzxp said:
I'll use v2 = v02 + 2a(s-s0). If I solve for a, maybe that will help get the frictional force?

yes, that will give you the deceleration …

then draw two free body diagrams, one for the truck and one for the trailer, and do F = ma for each …

what do you get? :smile:
 
I get:

FB = -11.25 kN
FT = -22.5 kN

I figure that to get the force in the coupling (C), that I need to subtract FB from FT which would give me FC = -11.25 kN



I know that fk = µN and that N in this case is -W. I'm not sure how to get the value for µ.
[PLAIN]http://www.fission-systems.com/images/physics/fma.png


Edit: I think I'll assume that it's on dry concrete and use µk = 0.8.
 
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i'm really not following that :confused:

µ is irrelevant, the forces can be found from the masses and the acceleration

your F = ma equations don't seem to include the force in the coupling (between the truck and the trailer) :redface:
 
your F = ma equations don't seem to include the force in the coupling (between the truck and the trailer)

I'm not exactly sure how to do that.
 
the trailer has only one horizontal force on it, the truck has two :wink:

(i'm assuming that the trailer wheels are not skidding, and that their moment of inertia is sufficiently small that you can ignore the friction)
 
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